Remove loose subsection
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@ -53,6 +53,3 @@ For every iteration of i in forward sweep we have 2 division, and 2 additions, r
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For backward sweep we have 1 division, and for every iteration of i we have 1 addition, and 1 division, resulting in $2(n-1)+1$ FLOPs.
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For backward sweep we have 1 division, and for every iteration of i we have 1 addition, and 1 division, resulting in $2(n-1)+1$ FLOPs.
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Total FLOPs for the special algorithm is $6(n-1)+1$.
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Total FLOPs for the special algorithm is $6(n-1)+1$.
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\subsection*{)}
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% Code
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