Update paper

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Cory Balaton 2023-09-25 14:21:09 +02:00
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6 changed files with 15 additions and 2 deletions

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@ -0,0 +1,13 @@
x,Vector 1,Vector 2,Vector 3,Analytic 1,Analytic 2,Analytic 3
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@ -12,5 +12,5 @@ Scaling will result in a dimensionless variable $\hat{x} = \frac{1}{L}$.
\end{align*}
Now we insert the expression into the original equation
\begin{align*}
\frac{d u(\hat{x})}{d\hat{x}^{2}} &= - \frac{F L^{2}}{\gamma} u(\hat{x}) \\
\frac{d u(\hat{x})}{d\hat{x}^{2}} &= - \frac{F L^{2}}{\gamma} u(\hat{x}). \\
\end{align*}