Merge pull request #8 from FYS3150-G2-2023/2-solve-problem-1
Solve problem 1
This commit is contained in:
commit
281261a798
Binary file not shown.
@ -89,7 +89,7 @@
|
|||||||
|
|
||||||
\textit{https://github.uio.no/FYS3150-G2-2023/Project-2}
|
\textit{https://github.uio.no/FYS3150-G2-2023/Project-2}
|
||||||
|
|
||||||
% \input{problems/problem-1}
|
\input{problems/problem-1}
|
||||||
|
|
||||||
% \input{problems/problem-2}
|
% \input{problems/problem-2}
|
||||||
|
|
||||||
|
|||||||
@ -0,0 +1,16 @@
|
|||||||
|
\section*{Problem 1}
|
||||||
|
We are studying the one-dimentional buckling beam, which can be described by the equation
|
||||||
|
\begin{align*}
|
||||||
|
\gamma \frac{d^{2} u(x)}{dx^{2}} &= -F u(x) & \rightarrow & & \frac{d^{2} u(x)}{dx^{2}} &= - \frac{F}{\gamma} u(x) \\
|
||||||
|
\end{align*}
|
||||||
|
where $\gamma$ is a constant determined by the material of the beam. We want to scale the equation, that is we want to scale by the x-value of the beams endpoint $x=L$.
|
||||||
|
Scaling will result in a dimensionless variable $\hat{x} = \frac{1}{L}$.
|
||||||
|
%
|
||||||
|
\begin{align*}
|
||||||
|
\frac{d^{2}}{dx^{2}} &= \frac{d}{dx} \frac{d}{dx} = \bigg( \frac{d\hat{x}}{dx} \frac{d}{d\hat{x}} \bigg) \bigg( \frac{d\hat{x}}{dx} \frac{d}{d\hat{x}} \bigg) & \text{where we have used } \frac{d\hat{x}}{dx} \frac{d}{d\hat{x}} = \frac{d}{dx} \frac{d\hat{x}}{d\hat{x}} \\
|
||||||
|
&= \bigg( \frac{1}{L} \frac{d}{d\hat{x}} \bigg) \bigg( \frac{1}{L} \frac{d}{d\hat{x}} \bigg) = \frac{1}{L^{2}} \frac{d}{d\hat{x}^{2}} & \text{where } \hat{x} \equiv \frac{x}{L} \text{ and } \frac{d\hat{x}}{dx} = \frac{1}{L} \\
|
||||||
|
\end{align*}
|
||||||
|
Now we insert the expression into the original equation
|
||||||
|
\begin{align*}
|
||||||
|
\frac{d u(\hat{x})}{d\hat{x}^{2}} &= - \frac{F L^{2}}{\gamma} u(\hat{x}) \\
|
||||||
|
\end{align*}
|
||||||
@ -0,0 +1,2 @@
|
|||||||
|
\section*{Problem 2}
|
||||||
|
|
||||||
@ -0,0 +1 @@
|
|||||||
|
\section*{Problem 3}
|
||||||
@ -0,0 +1 @@
|
|||||||
|
\section*{Problem 4}
|
||||||
@ -0,0 +1 @@
|
|||||||
|
\section*{Problem 5}
|
||||||
@ -0,0 +1 @@
|
|||||||
|
\section*{Problem 6}
|
||||||
Loading…
Reference in New Issue
Block a user