Produced plot with correct layout

latex/sections/results.tex

@@ -149,17 +149,18 @@ sharper when we increase lattice size, we are moving closer to the critical temp
 Based on the heat capacity (Figure \ref{fig:phase_heat_10M}) and susceptibility 
 (Figure \ref{fig:phase_susceptibility_10M}), we estimated the critical temperatures 
 of lattices of size $L \in \{20, 40, 60, 80, 100\}$ found in Table \ref{tab:critical_temperatures}.
+% Tc wide 10M = 2.37, 2.325, 2.3025, 2.295, 2.2875
 \begin{table}[H]
     \centering
     \begin{tabular}{cc} % @{\extracolsep{\fill}}
         \hline
         $L$ & $T_{c}(L)$ \\
         \hline 
-        $20$ & $ J / k_{B}$ \\
+        $20$ & $2.37 J / k_{B}$ \\
-        $40$ & $ J / k_{B}$ \\
+        $40$ & $2.325 J / k_{B}$ \\
-        $60$ & $ J / k_{B}$ \\
+        $60$ & $2.3025 J / k_{B}$ \\
-        $80$ & $ J / k_{B}$ \\
+        $80$ & $2.295 J / k_{B}$ \\
-        $100$ & $ J / k_{B}$ \\
+        $100$ & $2.2875 J / k_{B}$ \\
         \hline
     \end{tabular}
     \caption{Estimated critical temperatures for lattices $L \times L$, where $L$ denote the lattice size.}
@@ -172,16 +173,16 @@ we plot the critical temperatures $T_{c}(L)$ of the inverse lattice size $1/L$.
 the lattice size increase toward infinity, $1/L$ approaches zero. %
 \begin{figure}[H]
     \centering
-    \includegraphics[width=\linewidth]{../images/phase_transition/fox/wide/10M/linreg.pdf}
+    \includegraphics[width=\linewidth]{../images/phase_transition/fox/wide/1M/linreg.pdf}
     \caption{Linear regression, where $\beta_{0}$ is the intercept approximating $T_{c}(L = \infty)$, and $\beta_{1}$ is the slope.}
     \label{fig:linreg_10M}
 \end{figure}
-Using linear regression, we find the intercept which gives us an estimated value 
+We used linear regression to find the intercept $\beta_{0}$, which gives us an estimated value 
-of the critical temperature for a lattice of infinite size. We find the critical 
+of the critical temperature for a lattice of infinite size. The estimated critical temperature 
-temperature to be $T_{c \text{num}} \approx 2.2695 J/k_{B}$. We also compared the 
+is $T_{c \text{num}} \approx 2.2693 J/k_{B}$. We also compared the 
 estimate with the analytical solution, the relative error of our estimate is
 \begin{equation*}
-    \text{Relative error} =  \frac{T_{c \text{ numerical}} - T_{c \text{ analytical}}}{T_{c \text{ analytical}}} \approx 0.001 J/k_{B}
+    \text{Relative error} =  \frac{T_{c \text{ numerical}} - T_{c \text{ analytical}}}{T_{c \text{ analytical}}} \approx 5.05405 \cdot 10^{-5} J/k_{B}
 \end{equation*}
 
 \end{document}

python_scripts/phase_transition.py

@@ -212,7 +212,7 @@ def plot_phase_transition(indir, outdir):
     ax4.set_ylabel(r"$\chi$ $(1/J)$")
     ax4.legend(title="Lattice size", loc="upper right")
 
-    # ax5.legend()
+    # print(Tc)
 
     figure1.savefig(Path(outdir, "energy.pdf"), bbox_inches="tight")
     figure2.savefig(Path(outdir, "magnetization.pdf"), bbox_inches="tight")
@@ -228,7 +228,7 @@ def plot_phase_transition(indir, outdir):
 
 
 if __name__ == "__main__":
-    plot_phase_transition_alt(
+    plot_phase_transition(
         "data/fox/phase_transition/wide/10M/",
         "latex/images/phase_transition/fox/wide/10M/",
     )

python_scripts/timing.py

@@ -2,6 +2,20 @@ from os import makedirs
 from pathlib import Path
 
 import matplotlib.pyplot as plt
+import seaborn as sns
+
+sns.set_theme()
+params = {
+    "font.family": "Serif",
+    "font.serif": "Roman",
+    "text.usetex": True,
+    "axes.titlesize": "large",
+    "axes.labelsize": "large",
+    "xtick.labelsize": "large",
+    "ytick.labelsize": "large",
+    "legend.fontsize": "medium",
+}
+plt.rcParams.update(params)
 
 
 def plot_timing(indir, outdir):
@@ -35,9 +49,9 @@ def plot_timing(indir, outdir):
         ax1.set_xlabel(xlabel)
         ax1.set_ylabel("time (seconds)")
 
-        figure1.legend()
+        ax1.legend()
 
-        figure1.savefig(Path(outdir, outfile))
+        figure1.savefig(Path(outdir, outfile), bbox_inches="tight")
 
         plt.close(figure1)